50x^2-4.8x-0.8=0

Solution for 50x^2-4.8x-0.8=0 equation:

50x^2-4.8x-0.8=0

a = 50; b = -4.8; c = -0.8;
Δ = b2-4ac
Δ = -4.82-4·50·(-0.8)
Δ = 183.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.8)-\sqrt{183.04}}{2*50}=\frac{4.8-\sqrt{183.04}}{100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.8)+\sqrt{183.04}}{2*50}=\frac{4.8+\sqrt{183.04}}{100}
$